题意:~
思路:
#include <bits/stdc++.h>
using namespace std;
typedef long long LL;
template <class T> inline bool scan_d(T &ret) {char c; int sgn;if(c=getchar(),c==EOF) return 0;while(c!='-'&&(c<'0'||c>'9')) c=getchar(); sgn=(c=='-')?-1:1;ret=(c=='-')?0:(c-'0'); while(c=getchar(),c>='0'&&c<='9') ret=ret*10+(c-'0'); ret*=sgn;return 1;}
struct Trie {
int next[1050][26],fail[1050],end[1050];
int root,L;
int newnode()
{
for(int i = 0;i < 26;i++) next[L][i] = -1;
end[L++] = 0;
return L-1;
}
void init()
{
L = 0;
root = newnode();
}
void insert(char buf[])
{
int len = (int)strlen(buf);
int now = root;
for(int i = 0;i < len;i++)
{
if(next[now][buf[i]-'a'] == -1)
next[now][buf[i]-'a'] = newnode();
now = next[now][buf[i]-'a'];
}
end[now]++;
}
void build()
{
queue<int>Q;
fail[root] = root;
for(int i = 0;i < 26;i++)
if(next[root][i] == -1)
next[root][i] = root;
else
{
fail[next[root][i]] = root;
Q.push(next[root][i]);
}
while(!Q.empty())
{
int now = Q.front();
Q.pop();
if(end[fail[now]]) end[now]++;
for(int i = 0;i < 26;i++)
if(next[now][i] == -1)
{
next[now][i] = next[fail[now]][i];
}
else
{
fail[next[now][i]] = next[fail[now]][i];
Q.push(next[now][i]);
}
}
}
};
inline int cag(int x)
{
if(x == 0) return 'o' - 'a';
if(x == 1) return 'i' - 'a';
if(x == 3) return 'e' - 'a';
if(x == 5) return 's' - 'a';
if(x == 7) return 't' - 'a';
return - 1;
}
Trie ac;
const int mod = 1000003;
int dp[25][1005][10];
char str[25];
int main()
{
ios::sync_with_stdio(false);
cin.tie(0);
int l, r;
while(cin >> l >> r)
{
int m;
cin >> m;
ac.init();
for(int i = 0; i < m; ++i)
{
cin >> str;
ac.insert(str);
}
ac.build();
memset(dp, 0, sizeof(dp));
dp[0][0][0] = 1;
for(int i = 0; i < r; ++i)
{
for(int j = 0; j < ac.L; ++j)
{
for(int k = 0; k < 8; ++k)
{
if(dp[i][j][k] == 0) continue;
int last = dp[i][j][k];
int sta = 0;
for(int t = 0; t < 26; ++t)
{
int c = ac.next[j][t];
if(ac.end[c]) continue;
sta = k | 1;
dp[i + 1][c][sta] = (dp[i + 1][c][sta] + last) % mod;
sta = k | 2;
dp[i + 1][c][sta] = (dp[i + 1][c][sta] + last) % mod;
}
sta = k | 4;
for(int t = 0; t < 10; ++t)
{
int c = cag(t);
if(c == -1)
dp[i + 1][0][sta] = (dp[i + 1][0][sta] + last) % mod;
else
{
c = ac.next[j][c];
if(ac.end[c]) continue;
dp[i + 1][c][sta] = (dp[i + 1][c][sta] + last) % mod;
}
}
}
}
}
int ans = 0;
for(int i = l; i <= r; ++i)
{
for(int j = 0; j < ac.L; ++j)
ans = (ans + dp[i][j][7]) % mod;
}
cout << ans << "\n";
}
return 0;
}
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