按题意直接搞就可以了,就是写起来比较麻烦。。。
#include<iostream>
#include<cstdio>
#include<string>
#include<string.h>
#include<algorithm>
#include<cstdlib>
#include<ctime>
#include<cmath>
#include<iomanip>
#include<map>
#include<vector>
#include<queue>
#include<stack>
//#include<bits/stdc++.h>
using namespace std;
typedef long long LL;
const int INF = 0x3f3f3f3f;
const int N = 1050;
char str[15];
int main()
{
int t;
cin>>t;
int a,b;
while(t--)
{
LL sum=0;
int n;
scanf("%d",&n);
scanf("%d%d",&a,&b);
getchar();
for(int i=0; i<n; ++i)
{
//cout<<sum<<endl;
gets(str);
bool flag=0;
if(str[6]-'0'==str[7]-'0' && str[7]-'0'==str[8]-'0' && str[8]-'0'==str[9]-'0' && str[9]-'0'==str[10]-'0')
{
flag=1;
}
if(str[6]-'0'+1==str[7]-'0' && str[7]-'0'+1==str[8]-'0' && str[8]-'0'+1==str[9]-'0' && str[9]-'0'+1==str[10]-'0')
{
flag=1;
}
if(str[6]-'0'-1==str[7]-'0' && str[7]-'0'-1==str[8]-'0' && str[8]-'0'-1==str[9]-'0' && str[9]-'0'-1==str[10]-'0')
{
flag=1;
}
if(flag==1)
{
sum+=a;
continue;
}
int nian=(str[3]-'0')*1000+(str[4]-'0')*100+(str[5]-'0')*10+(str[6]-'0')*1;
int yue=(str[7]-'0')*10+(str[8]-'0')*1;
int ri=(str[9]-'0')*10+(str[10]-'0')*1;
// cout<<yue<<" "<<ri<<endl;
if(nian<1980 || nian >2016)
{
sum+=b;
continue;
}
if(yue<1 || yue >12)
{
sum+=b;
continue;
}
if(ri<1 || ri >31)
{
sum+=b;
continue;
}
if( (nian%4==0 && nian%100!=0) || (nian%400==0) )
{
// cout<<"199"<<endl;
if(yue==2)
{
if(ri<=29 && ri>=1)
flag=1;
}
else if(yue==1 || yue==3 ||yue==5 ||yue==7 ||yue==8 ||yue==10 ||yue==12)
{
if(ri<=31 && ri>=1)
flag=1;
}
else if(yue==4 || yue==6 ||yue==9 ||yue==11)
{
if(ri<=30 && ri>=1)
flag=1;
}
}
else
{
// cout<<"asd"<<endl;
if(yue==2)
{
if(ri<=28 && ri>=1)
flag=1;
}
else if(yue==1 || yue==3 ||yue==5 ||yue==7 ||yue==8 ||yue==10 ||yue==12)
{
if(ri<=31 && ri>=1)
flag=1;
}
else if(yue==4 || yue==6 ||yue==9 ||yue==11)
{
if(ri<=30 && ri>=1)
flag=1;
}
}
if(flag==1)
sum+=a;
else
sum+=b;
}
cout<<sum<<endl;
}
return 0;
}
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